What are the solutions to the equation 4(x-9)(5x+1)=0 ?

The solutions to the equation 4(x-9)(5x+1)=0 are x=9,x=-1/5

Find the zeros of 4(x-9)(5x+1)=0

The zeros of 4(x-9)(5x+1)=0 are x=9,x=-1/5

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4 (x - 9) (5 x + 1) = 0

x = 9, x = - \frac{1}{5}

Decimal Notation

x = 9, x = - 0.2

Solution steps

4 (x - 9) (5 x + 1) = 0

Using the Zero Factor Principle:

ab = 0

then

a = 0

b = 0

x - 9 = 0 or 5 x + 1 = 0

Solve

x - 9 = 0 : x = 9

Solve

5 x + 1 = 0 : x = - \frac{1}{5}

The solutions to the quadratic equation are:

x = 9, x = - \frac{1}{5}

x, y^{3} + x y + x^{2} = 3

9 - x^{2} - 1 = - 2 x (x - 1)

(x - 3) (x - 2) = 12

9^{2} + x^{2} = 1 1^{2}

y, 2 x + y^{2} = 48

What are the solutions to the equation 4(x-9)(5x+1)=0 ?
The solutions to the equation 4(x-9)(5x+1)=0 are x=9,x=-1/5
Find the zeros of 4(x-9)(5x+1)=0
The zeros of 4(x-9)(5x+1)=0 are x=9,x=-1/5