What are the solutions to the equation x^2-18x+21=-3x ?

The solutions to the equation x^2-18x+21=-3x are x=(15+sqrt(141))/2 ,x=(15-sqrt(141))/2

Find the zeros of x^2-18x+21=-3x

The zeros of x^2-18x+21=-3x are x=(15+sqrt(141))/2 ,x=(15-sqrt(141))/2

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x^{2} - 18 x + 21 = - 3 x

x = \frac{15 + 141}{2}, x = \frac{15 - 141}{2}

Decimal Notation

x = 13.43717 \dots, x = 1.56282 \dots

Solution steps

x^{2} - 18 x + 21 = - 3 x

Move

3 x

to the left side

x^{2} - 15 x + 21 = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- ( - 15 ) \pm ( - 15 ) ^{2} - 4 \cdot 1 \cdot 21}{2 \cdot 1}

(- 15)^{2} - 4 \cdot 1 \cdot 21 = 141

x_{1, 2} = \frac{- ( - 15 ) \pm 141}{2 \cdot 1}

Separate the solutions

x_{1} = \frac{- ( - 15 ) + 141}{2 \cdot 1}, x_{2} = \frac{- ( - 15 ) - 141}{2 \cdot 1}

x = \frac{- ( - 15 ) + 141}{2 \cdot 1} : \frac{15 + 141}{2}

x = \frac{- ( - 15 ) - 141}{2 \cdot 1} : \frac{15 - 141}{2}

The solutions to the quadratic equation are:

x = \frac{15 + 141}{2}, x = \frac{15 - 141}{2}

(x + 1)^{2} + (x + 2)^{2} + (x + 3)^{2} = x^{2} + 12 x + 64

6 x^{2} - 5 x + 7 = 4 x^{2} + 11

3 x^{2} + 12 x + 9

- 4 x^{2} + 4 x + 1 = 0

0 = y (y - 1)

What are the solutions to the equation x^2-18x+21=-3x ?
The solutions to the equation x^2-18x+21=-3x are x=(15+sqrt(141))/2 ,x=(15-sqrt(141))/2
Find the zeros of x^2-18x+21=-3x
The zeros of x^2-18x+21=-3x are x=(15+sqrt(141))/2 ,x=(15-sqrt(141))/2