What are the solutions to the equation 6x^2-5x+7=4x^2+11 ?

The solutions to the equation 6x^2-5x+7=4x^2+11 are x=(5+sqrt(57))/4 ,x=(5-sqrt(57))/4

Find the zeros of 6x^2-5x+7=4x^2+11

The zeros of 6x^2-5x+7=4x^2+11 are x=(5+sqrt(57))/4 ,x=(5-sqrt(57))/4

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

Popular >

6 x^{2} - 5 x + 7 = 4 x^{2} + 11

x = \frac{5 + 57}{4}, x = \frac{5 - 57}{4}

Decimal Notation

x = 3.13745 \dots, x = - 0.63745 \dots

Solution steps

6 x^{2} - 5 x + 7 = 4 x^{2} + 11

Move

11

to the left side

6 x^{2} - 5 x - 4 = 4 x^{2}

Move

4 x^{2}

to the left side

2 x^{2} - 5 x - 4 = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- ( - 5 ) \pm ( - 5 ) ^{2} - 4 \cdot 2 ( - 4 )}{2 \cdot 2}

(- 5)^{2} - 4 \cdot 2 (- 4) = 57

x_{1, 2} = \frac{- ( - 5 ) \pm 57}{2 \cdot 2}

Separate the solutions

x_{1} = \frac{- ( - 5 ) + 57}{2 \cdot 2}, x_{2} = \frac{- ( - 5 ) - 57}{2 \cdot 2}

x = \frac{- ( - 5 ) + 57}{2 \cdot 2} : \frac{5 + 57}{4}

x = \frac{- ( - 5 ) - 57}{2 \cdot 2} : \frac{5 - 57}{4}

The solutions to the quadratic equation are:

x = \frac{5 + 57}{4}, x = \frac{5 - 57}{4}

3 x^{2} + 12 x + 9

- 4 x^{2} + 4 x + 1 = 0

0 = y (y - 1)

7 - 12 x - 18 x^{2}

x^{2} - 5 x - 6 = 3

What are the solutions to the equation 6x^2-5x+7=4x^2+11 ?
The solutions to the equation 6x^2-5x+7=4x^2+11 are x=(5+sqrt(57))/4 ,x=(5-sqrt(57))/4
Find the zeros of 6x^2-5x+7=4x^2+11
The zeros of 6x^2-5x+7=4x^2+11 are x=(5+sqrt(57))/4 ,x=(5-sqrt(57))/4