What are the solutions to the equation completesquare 7-12x-18x^2 ?

The solutions to the equation completesquare 7-12x-18x^2 are -18(x+1/3)^2+9

Find the zeros of completesquare 7-12x-18x^2

The zeros of completesquare 7-12x-18x^2 are -18(x+1/3)^2+9

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complete the square

7 - 12 x - 18 x^{2}

- 18 (x + \frac{1}{3})^{2} + 9

Solution steps

7 - 12 x - 18 x^{2}

Write in the standard form

a x^{2} + b x + c

- 18 x^{2} - 12 x + 7

Write

- 18 x^{2} - 12 x + 7

in the form:

x^{2} + 2 a x + a^{2}

Factor out

- 18

- 18 (x^{2} + \frac{2 x}{3} - \frac{7}{18})

2 a = \frac{2}{3} : a = \frac{1}{3}

Add and subtract

(\frac{1}{3})^{2}

- 18 (x^{2} + \frac{2 x}{3} - \frac{7}{18} + (\frac{1}{3})^{2} - (\frac{1}{3})^{2})

x^{2} + 2 a x + a^{2} = (x + a)^{2}

x^{2} + \frac{2}{3} x + (\frac{1}{3})^{2} = (x + \frac{1}{3})^{2}

- 18 ((x + \frac{1}{3})^{2} - \frac{7}{18} - (\frac{1}{3})^{2})

Simplify

- 18 (x + \frac{1}{3})^{2} + 9

x^{2} - 5 x - 6 = 3

r^{2} - 3 r - 1 = 0

3 x^{2} + 32 x + 80 = 0

q^{2} - 4 = 0

x, x^{2} y + x y^{2} = 2

What are the solutions to the equation completesquare 7-12x-18x^2 ?
The solutions to the equation completesquare 7-12x-18x^2 are -18(x+1/3)^2+9
Find the zeros of completesquare 7-12x-18x^2
The zeros of completesquare 7-12x-18x^2 are -18(x+1/3)^2+9