What are the solutions to the equation (x^2+4x)/5 =0.75 ?

The solutions to the equation (x^2+4x)/5 =0.75 are x=(-4+sqrt(31))/2 ,x=-(4+sqrt(31))/2

Find the zeros of (x^2+4x)/5 =0.75

The zeros of (x^2+4x)/5 =0.75 are x=(-4+sqrt(31))/2 ,x=-(4+sqrt(31))/2

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\frac{x ^{2} + 4 x}{5} = 0.75

x = \frac{- 4 + 31}{2}, x = - \frac{4 + 31}{2}

Decimal Notation

x = 0.78388 \dots, x = - 4.78388 \dots

Solution steps

\frac{x ^{2} + 4 x}{5} = 0.75

Multiply both sides by

100

20 (x^{2} + 4 x) = 75

Expand

20 (x^{2} + 4 x) : 20 x^{2} + 80 x

20 x^{2} + 80 x = 75

Move

75

to the left side

20 x^{2} + 80 x - 75 = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- 80 \pm 8 0 ^{2} - 4 \cdot 20 ( - 75 )}{2 \cdot 20}

8 0^{2} - 4 \cdot 20 (- 75) = 2031

x_{1, 2} = \frac{- 80 \pm 20 31}{2 \cdot 20}

Separate the solutions

x_{1} = \frac{- 80 + 20 31}{2 \cdot 20}, x_{2} = \frac{- 80 - 20 31}{2 \cdot 20}

x = \frac{- 80 + 20 31}{2 \cdot 20} : \frac{- 4 + 31}{2}

x = \frac{- 80 - 20 31}{2 \cdot 20} : - \frac{4 + 31}{2}

The solutions to the quadratic equation are:

x = \frac{- 4 + 31}{2}, x = - \frac{4 + 31}{2}

100 x^{2} - 121 = 0

(2 x + 1) 2 = 1 + (x + 1) (x - 1)

a^{2} = 26

v^{2} - 5 v + 6 = 0

x, \frac{x ^{2}}{c ^{2}} - \frac{y ^{9}}{d ^{2}} = π x

What are the solutions to the equation (x^2+4x)/5 =0.75 ?
The solutions to the equation (x^2+4x)/5 =0.75 are x=(-4+sqrt(31))/2 ,x=-(4+sqrt(31))/2
Find the zeros of (x^2+4x)/5 =0.75
The zeros of (x^2+4x)/5 =0.75 are x=(-4+sqrt(31))/2 ,x=-(4+sqrt(31))/2