What are the solutions to the equation p^2+4p+4=0 ?

The solutions to the equation p^2+4p+4=0 are p=-2

Find the zeros of p^2+4p+4=0

The zeros of p^2+4p+4=0 are p=-2

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p^{2} + 4 p + 4 = 0

p = - 2

Solution steps

p^{2} + 4 p + 4 = 0

Solve with the quadratic formula

p_{1, 2} = \frac{- 4 \pm 4 ^{2} - 4 \cdot 1 \cdot 4}{2 \cdot 1}

4^{2} - 4 \cdot 1 \cdot 4 = 0

p_{1, 2} = \frac{- 4 \pm 0}{2 \cdot 1}

p = \frac{- 4}{2 \cdot 1}

\frac{- 4}{2 \cdot 1} = - 2

p = - 2

The solution to the quadratic equation is:

p = - 2

6 x^{2} + 2 x = 216

(2 x - 7) (x + 3) + 30 = x (1 - x)

64 = 2 x^{2}

4 x^{2} + 28 x + 49 = 0

x^{2} + 100 x + 10000 = 0

What are the solutions to the equation p^2+4p+4=0 ?
The solutions to the equation p^2+4p+4=0 are p=-2
Find the zeros of p^2+4p+4=0
The zeros of p^2+4p+4=0 are p=-2