What are the solutions to the equation 4x^2-2x=7 ?

The solutions to the equation 4x^2-2x=7 are x=(1+sqrt(29))/4 ,x=(1-sqrt(29))/4

Find the zeros of 4x^2-2x=7

The zeros of 4x^2-2x=7 are x=(1+sqrt(29))/4 ,x=(1-sqrt(29))/4

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

Popular >

4 x^{2} - 2 x = 7

x = \frac{1 + 29}{4}, x = \frac{1 - 29}{4}

Decimal Notation

x = 1.59629 \dots, x = - 1.09629 \dots

Solution steps

4 x^{2} - 2 x = 7

Move

7

to the left side

4 x^{2} - 2 x - 7 = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- ( - 2 ) \pm ( - 2 ) ^{2} - 4 \cdot 4 ( - 7 )}{2 \cdot 4}

(- 2)^{2} - 4 \cdot 4 (- 7) = 229

x_{1, 2} = \frac{- ( - 2 ) \pm 2 29}{2 \cdot 4}

Separate the solutions

x_{1} = \frac{- ( - 2 ) + 2 29}{2 \cdot 4}, x_{2} = \frac{- ( - 2 ) - 2 29}{2 \cdot 4}

x = \frac{- ( - 2 ) + 2 29}{2 \cdot 4} : \frac{1 + 29}{4}

x = \frac{- ( - 2 ) - 2 29}{2 \cdot 4} : \frac{1 - 29}{4}

The solutions to the quadratic equation are:

x = \frac{1 + 29}{4}, x = \frac{1 - 29}{4}

18 = - 16 x^{2} + 16 x + 12

7 (x^{2} - 9) = (x - 3)

4 x^{2} + 8 x - 320 = 0

(x - 2) (x + 4) - 2 (x - 4) = 0

3 y^{2} - 4 y + 2 = 2 (y - 3) 2

What are the solutions to the equation 4x^2-2x=7 ?
The solutions to the equation 4x^2-2x=7 are x=(1+sqrt(29))/4 ,x=(1-sqrt(29))/4
Find the zeros of 4x^2-2x=7
The zeros of 4x^2-2x=7 are x=(1+sqrt(29))/4 ,x=(1-sqrt(29))/4