What are the solutions to the equation 0=2x^2-12x-30 ?

The solutions to the equation 0=2x^2-12x-30 are x=3+2sqrt(6),x=3-2sqrt(6)

Find the zeros of 0=2x^2-12x-30

The zeros of 0=2x^2-12x-30 are x=3+2sqrt(6),x=3-2sqrt(6)

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0 = 2 x^{2} - 12 x - 30

x = 3 + 26, x = 3 - 26

Decimal Notation

x = 7.89897 \dots, x = - 1.89897 \dots

Solution steps

0 = 2 x^{2} - 12 x - 30

Switch sides

2 x^{2} - 12 x - 30 = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- ( - 12 ) \pm ( - 12 ) ^{2} - 4 \cdot 2 ( - 30 )}{2 \cdot 2}

(- 12)^{2} - 4 \cdot 2 (- 30) = 86

x_{1, 2} = \frac{- ( - 12 ) \pm 8 6}{2 \cdot 2}

Separate the solutions

x_{1} = \frac{- ( - 12 ) + 8 6}{2 \cdot 2}, x_{2} = \frac{- ( - 12 ) - 8 6}{2 \cdot 2}

x = \frac{- ( - 12 ) + 8 6}{2 \cdot 2} : 3 + 26

x = \frac{- ( - 12 ) - 8 6}{2 \cdot 2} : 3 - 26

The solutions to the quadratic equation are:

x = 3 + 26, x = 3 - 26

1.1 t^{2} - 1.2 t + 0.3 = 0

x^{2} - 10 x - 96 = 0

(2 x - 3) (x - 5) = 0

375 x^{2} - 31815 x + 675 = 0

45 m^{2} + 725 m + 144 = 0

What are the solutions to the equation 0=2x^2-12x-30 ?
The solutions to the equation 0=2x^2-12x-30 are x=3+2sqrt(6),x=3-2sqrt(6)
Find the zeros of 0=2x^2-12x-30
The zeros of 0=2x^2-12x-30 are x=3+2sqrt(6),x=3-2sqrt(6)