What are the solutions to the equation x^2-5x-150=0 ?

The solutions to the equation x^2-5x-150=0 are x=15,x=-10

Find the zeros of x^2-5x-150=0

The zeros of x^2-5x-150=0 are x=15,x=-10

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x^{2} - 5 x - 150 = 0

x = 15, x = - 10

Solution steps

x^{2} - 5 x - 150 = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- ( - 5 ) \pm ( - 5 ) ^{2} - 4 \cdot 1 \cdot ( - 150 )}{2 \cdot 1}

(- 5)^{2} - 4 \cdot 1 \cdot (- 150) = 25

x_{1, 2} = \frac{- ( - 5 ) \pm 25}{2 \cdot 1}

Separate the solutions

x_{1} = \frac{- ( - 5 ) + 25}{2 \cdot 1}, x_{2} = \frac{- ( - 5 ) - 25}{2 \cdot 1}

x = \frac{- ( - 5 ) + 25}{2 \cdot 1} : 15

x = \frac{- ( - 5 ) - 25}{2 \cdot 1} : - 10

The solutions to the quadratic equation are:

x = 15, x = - 10

v^{2} - 2 v = 3

2 (x - 3)^{2} + (7 x - 21) - 15 = 0

a^{2} - 9 a + 2 = 0

x^{2} + (1 - 2 k) x + (k^{2} - k - 2) = 0

x^{2} - 13 x - 420 = 0

What are the solutions to the equation x^2-5x-150=0 ?
The solutions to the equation x^2-5x-150=0 are x=15,x=-10
Find the zeros of x^2-5x-150=0
The zeros of x^2-5x-150=0 are x=15,x=-10