What is x^4-25x^2+144<= 0 ?

The solution to x^4-25x^2+144<= 0 is -4<= x<=-3\lor 3<= x<= 4

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x^4-25x^2+144<= 0

x^{4} - 25 x^{2} + 144 \leq 0

- 4 \leq x \leq - 3 or 3 \leq x \leq 4

Interval Notation

[- 4, - 3] \cup [3, 4]

Solution steps

x^{4} - 25 x^{2} + 144 \leq 0

Factor

x^{4} - 25 x^{2} + 144 : (x + 3) (x - 3) (x + 4) (x - 4)

(x + 3) (x - 3) (x + 4) (x - 4) \leq 0

Identify the intervals

- 4 \leq x \leq - 3 or 3 \leq x \leq 4

\frac{5 - 7}{9 - 14}

(\frac{25}{64})^{\frac{3}{2}}

6 x + 1 < - \frac{5 x}{3} + 5

\frac{1}{6} < \frac{2 x - 13}{12} \leq \frac{2}{3}

12 (x)^{2} + 12 x = 826

What is x^4-25x^2+144<= 0 ?
The solution to x^4-25x^2+144<= 0 is -4<= x<=-3\lor 3<= x<= 4