What are the solutions to the equation n^2-5n=-4 ?

The solutions to the equation n^2-5n=-4 are n=4,n=1

Find the zeros of n^2-5n=-4

The zeros of n^2-5n=-4 are n=4,n=1

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n^{2} - 5 n = - 4

n = 4, n = 1

Solution steps

n^{2} - 5 n = - 4

Move

4

to the left side

n^{2} - 5 n + 4 = 0

Solve with the quadratic formula

n_{1, 2} = \frac{- ( - 5 ) \pm ( - 5 ) ^{2} - 4 \cdot 1 \cdot 4}{2 \cdot 1}

(- 5)^{2} - 4 \cdot 1 \cdot 4 = 3

n_{1, 2} = \frac{- ( - 5 ) \pm 3}{2 \cdot 1}

Separate the solutions

n_{1} = \frac{- ( - 5 ) + 3}{2 \cdot 1}, n_{2} = \frac{- ( - 5 ) - 3}{2 \cdot 1}

n = \frac{- ( - 5 ) + 3}{2 \cdot 1} : 4

n = \frac{- ( - 5 ) - 3}{2 \cdot 1} : 1

The solutions to the quadratic equation are:

n = 4, n = 1

x, 3 x^{2} - y^{2} = C

x^{2} + 14 x + 21 = 0

x, e^{f} = 1 + x^{2}

a^{2} + 5^{2} = 8^{2}

4 x^{2} - 8 x - 3 = 0

What are the solutions to the equation n^2-5n=-4 ?
The solutions to the equation n^2-5n=-4 are n=4,n=1
Find the zeros of n^2-5n=-4
The zeros of n^2-5n=-4 are n=4,n=1