What are the solutions to the equation solvefor x,e^f=1+x^2 ?

The solutions to the equation solvefor x,e^f=1+x^2 are x=sqrt(e^f-1),x=-sqrt(e^f-1)

Find the zeros of solvefor x,e^f=1+x^2

The zeros of solvefor x,e^f=1+x^2 are x=sqrt(e^f-1),x=-sqrt(e^f-1)

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solve for

x, e^{f} = 1 + x^{2}

x = e^{f} - 1, x = - e^{f} - 1

Solution steps

e^{f} = 1 + x^{2}

Switch sides

1 + x^{2} = e^{f}

Move

1

to the right side

x^{2} = e^{f} - 1

For

x^{2} = f (a)

the solutions are

x = f (a), - f (a)

x = e^{f} - 1, x = - e^{f} - 1

a^{2} + 5^{2} = 8^{2}

4 x^{2} - 8 x - 3 = 0

(2 y + 7) (2 - y) = 0

y, 20 x^{3} y + 6 y = 5 x^{4} + 6 x + 3 y^{2}

4 m^{2} - 18 = 3 m

What are the solutions to the equation solvefor x,e^f=1+x^2 ?
The solutions to the equation solvefor x,e^f=1+x^2 are x=sqrt(e^f-1),x=-sqrt(e^f-1)
Find the zeros of solvefor x,e^f=1+x^2
The zeros of solvefor x,e^f=1+x^2 are x=sqrt(e^f-1),x=-sqrt(e^f-1)