What are the solutions to the equation 4m^2-18=3m ?

The solutions to the equation 4m^2-18=3m are m=(3+3sqrt(33))/8 ,m=(3-3sqrt(33))/8

Find the zeros of 4m^2-18=3m

The zeros of 4m^2-18=3m are m=(3+3sqrt(33))/8 ,m=(3-3sqrt(33))/8

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4 m^{2} - 18 = 3 m

m = \frac{3 + 3 33}{8}, m = \frac{3 - 3 33}{8}

Decimal Notation

m = 2.52921 \dots, m = - 1.77921 \dots

Solution steps

4 m^{2} - 18 = 3 m

Move

3 m

to the left side

4 m^{2} - 18 - 3 m = 0

Write in the standard form

a x^{2} + b x + c = 0

4 m^{2} - 3 m - 18 = 0

Solve with the quadratic formula

m_{1, 2} = \frac{- ( - 3 ) \pm ( - 3 ) ^{2} - 4 \cdot 4 ( - 18 )}{2 \cdot 4}

(- 3)^{2} - 4 \cdot 4 (- 18) = 333

m_{1, 2} = \frac{- ( - 3 ) \pm 3 33}{2 \cdot 4}

Separate the solutions

m_{1} = \frac{- ( - 3 ) + 3 33}{2 \cdot 4}, m_{2} = \frac{- ( - 3 ) - 3 33}{2 \cdot 4}

m = \frac{- ( - 3 ) + 3 33}{2 \cdot 4} : \frac{3 + 3 33}{8}

m = \frac{- ( - 3 ) - 3 33}{2 \cdot 4} : \frac{3 - 3 33}{8}

The solutions to the quadratic equation are:

m = \frac{3 + 3 33}{8}, m = \frac{3 - 3 33}{8}

(2 y - 1) (y - 2) = 0

- x^{2} - 7 x = - 18

x^{2} + 10 x + \frac{25}{2} = 0

t^{2} = 5 t - 6

2808.8 = 0.68 \cdot 2.14 \cdot 100 \cdot x \cdot (9.5 - 0.4 \cdot x)

What are the solutions to the equation 4m^2-18=3m ?
The solutions to the equation 4m^2-18=3m are m=(3+3sqrt(33))/8 ,m=(3-3sqrt(33))/8
Find the zeros of 4m^2-18=3m
The zeros of 4m^2-18=3m are m=(3+3sqrt(33))/8 ,m=(3-3sqrt(33))/8