What are the solutions to the equation -x^2-7x=-18 ?

The solutions to the equation -x^2-7x=-18 are x=-9,x=2

Find the zeros of -x^2-7x=-18

The zeros of -x^2-7x=-18 are x=-9,x=2

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- x^{2} - 7 x = - 18

x = - 9, x = 2

Solution steps

- x^{2} - 7 x = - 18

Move

18

to the left side

- x^{2} - 7 x + 18 = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- ( - 7 ) \pm ( - 7 ) ^{2} - 4 ( - 1 ) \cdot 18}{2 ( - 1 )}

(- 7)^{2} - 4 (- 1) \cdot 18 = 11

x_{1, 2} = \frac{- ( - 7 ) \pm 11}{2 ( - 1 )}

Separate the solutions

x_{1} = \frac{- ( - 7 ) + 11}{2 ( - 1 )}, x_{2} = \frac{- ( - 7 ) - 11}{2 ( - 1 )}

x = \frac{- ( - 7 ) + 11}{2 ( - 1 )} : - 9

x = \frac{- ( - 7 ) - 11}{2 ( - 1 )} : 2

The solutions to the quadratic equation are:

x = - 9, x = 2

x^{2} + 10 x + \frac{25}{2} = 0

t^{2} = 5 t - 6

2808.8 = 0.68 \cdot 2.14 \cdot 100 \cdot x \cdot (9.5 - 0.4 \cdot x)

2 x^{2} - 2 x + 3 = x^{2} - 3 x + 2

x, 2 x^{2} + 2 x y + y^{2} = 2

What are the solutions to the equation -x^2-7x=-18 ?
The solutions to the equation -x^2-7x=-18 are x=-9,x=2
Find the zeros of -x^2-7x=-18
The zeros of -x^2-7x=-18 are x=-9,x=2