What are the solutions to the equation x^2+10x+25/2 =0 ?

The solutions to the equation x^2+10x+25/2 =0 are x=(5(sqrt(2)-2))/2 ,x=-(5(2+sqrt(2)))/2

Find the zeros of x^2+10x+25/2 =0

The zeros of x^2+10x+25/2 =0 are x=(5(sqrt(2)-2))/2 ,x=-(5(2+sqrt(2)))/2

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x^{2} + 10 x + \frac{25}{2} = 0

x = \frac{5 ( 2 - 2 )}{2}, x = - \frac{5 ( 2 + 2 )}{2}

Decimal Notation

x = - 1.46446 \dots, x = - 8.53553 \dots

Solution steps

x^{2} + 10 x + \frac{25}{2} = 0

Multiply both sides by

2

2 x^{2} + 20 x + 25 = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- 20 \pm 2 0 ^{2} - 4 \cdot 2 \cdot 25}{2 \cdot 2}

2 0^{2} - 4 \cdot 2 \cdot 25 = 102

x_{1, 2} = \frac{- 20 \pm 10 2}{2 \cdot 2}

Separate the solutions

x_{1} = \frac{- 20 + 10 2}{2 \cdot 2}, x_{2} = \frac{- 20 - 10 2}{2 \cdot 2}

x = \frac{- 20 + 10 2}{2 \cdot 2} : \frac{5 ( 2 - 2 )}{2}

x = \frac{- 20 - 10 2}{2 \cdot 2} : - \frac{5 ( 2 + 2 )}{2}

The solutions to the quadratic equation are:

x = \frac{5 ( 2 - 2 )}{2}, x = - \frac{5 ( 2 + 2 )}{2}

t^{2} = 5 t - 6

2808.8 = 0.68 \cdot 2.14 \cdot 100 \cdot x \cdot (9.5 - 0.4 \cdot x)

2 x^{2} - 2 x + 3 = x^{2} - 3 x + 2

x, 2 x^{2} + 2 x y + y^{2} = 2

x^{2} - 4 x + 0 = 0

What are the solutions to the equation x^2+10x+25/2 =0 ?
The solutions to the equation x^2+10x+25/2 =0 are x=(5(sqrt(2)-2))/2 ,x=-(5(2+sqrt(2)))/2
Find the zeros of x^2+10x+25/2 =0
The zeros of x^2+10x+25/2 =0 are x=(5(sqrt(2)-2))/2 ,x=-(5(2+sqrt(2)))/2