What are the solutions to the equation quadraticformula x^2-4x+0=0 ?

The solutions to the equation quadraticformula x^2-4x+0=0 are x=4,x=0

Find the zeros of quadraticformula x^2-4x+0=0

The zeros of quadraticformula x^2-4x+0=0 are x=4,x=0

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x^{2} - 4 x + 0 = 0

x = 4, x = 0

Solution steps

x^{2} - 4 x + 0 = 0

Refine

x^{2} - 4 x = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- ( - 4 ) \pm ( - 4 ) ^{2} - 4 \cdot 1 \cdot 0}{2 \cdot 1}

(- 4)^{2} - 4 \cdot 1 \cdot 0 = 4

x_{1, 2} = \frac{- ( - 4 ) \pm 4}{2 \cdot 1}

Separate the solutions

x_{1} = \frac{- ( - 4 ) + 4}{2 \cdot 1}, x_{2} = \frac{- ( - 4 ) - 4}{2 \cdot 1}

x = \frac{- ( - 4 ) + 4}{2 \cdot 1} : 4

x = \frac{- ( - 4 ) - 4}{2 \cdot 1} : 0

The solutions to the quadratic equation are:

x = 4, x = 0

x, x^{2} - 3 x - 28 = 0

6 x^{2} + 9 x = 0

x^{2} + 11 x - 242 = 0

a, c^{2} = a^{2} - b^{2}

p^{2} = 4 p

What are the solutions to the equation quadraticformula x^2-4x+0=0 ?
The solutions to the equation quadraticformula x^2-4x+0=0 are x=4,x=0
Find the zeros of quadraticformula x^2-4x+0=0
The zeros of quadraticformula x^2-4x+0=0 are x=4,x=0