What are the solutions to the equation r^2+40r+2000=0 ?

The solutions to the equation r^2+40r+2000=0 are r=-20+40i,r=-20-40i

Find the zeros of r^2+40r+2000=0

The zeros of r^2+40r+2000=0 are r=-20+40i,r=-20-40i

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r^{2} + 40 r + 2000 = 0

r = - 20 + 40 i, r = - 20 - 40 i

Solution steps

r^{2} + 40 r + 2000 = 0

Solve with the quadratic formula

r_{1, 2} = \frac{- 40 \pm 4 0 ^{2} - 4 \cdot 1 \cdot 2000}{2 \cdot 1}

Simplify

4 0^{2} - 4 \cdot 1 \cdot 2000 : 80 i

r_{1, 2} = \frac{- 40 \pm 80 i}{2 \cdot 1}

Separate the solutions

r_{1} = \frac{- 40 + 80 i}{2 \cdot 1}, r_{2} = \frac{- 40 - 80 i}{2 \cdot 1}

r = \frac{- 40 + 80 i}{2 \cdot 1} : - 20 + 40 i

r = \frac{- 40 - 80 i}{2 \cdot 1} : - 20 - 40 i

The solutions to the quadratic equation are:

r = - 20 + 40 i, r = - 20 - 40 i

(y - 4)^{2} = (y - 4) (- y + 1)

2 x = x^{2} - 15

z^{2} + 2 z^{2} + z - z + 9 = 0

x, - x^{2} - 2 y^{3} + 2 y^{2} = 0

2 x^{2} + 4 x - 6

What are the solutions to the equation r^2+40r+2000=0 ?
The solutions to the equation r^2+40r+2000=0 are r=-20+40i,r=-20-40i
Find the zeros of r^2+40r+2000=0
The zeros of r^2+40r+2000=0 are r=-20+40i,r=-20-40i