What are the solutions to the equation 5x^2+6x-4=0 ?

The solutions to the equation 5x^2+6x-4=0 are x=(-3+sqrt(29))/5 ,x=-(3+sqrt(29))/5

Find the zeros of 5x^2+6x-4=0

The zeros of 5x^2+6x-4=0 are x=(-3+sqrt(29))/5 ,x=-(3+sqrt(29))/5

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5 x^{2} + 6 x - 4 = 0

x = \frac{- 3 + 29}{5}, x = - \frac{3 + 29}{5}

Decimal Notation

x = 0.47703 \dots, x = - 1.67703 \dots

Solution steps

5 x^{2} + 6 x - 4 = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- 6 \pm 6 ^{2} - 4 \cdot 5 ( - 4 )}{2 \cdot 5}

6^{2} - 4 \cdot 5 (- 4) = 229

x_{1, 2} = \frac{- 6 \pm 2 29}{2 \cdot 5}

Separate the solutions

x_{1} = \frac{- 6 + 2 29}{2 \cdot 5}, x_{2} = \frac{- 6 - 2 29}{2 \cdot 5}

x = \frac{- 6 + 2 29}{2 \cdot 5} : \frac{- 3 + 29}{5}

x = \frac{- 6 - 2 29}{2 \cdot 5} : - \frac{3 + 29}{5}

The solutions to the quadratic equation are:

x = \frac{- 3 + 29}{5}, x = - \frac{3 + 29}{5}

x, b^{2} x^{2} - a^{2} y^{2} = a^{2} b^{2}

1 0^{2} + x^{2} = 6^{2}

3 x (x - 2) - (x - 6) = 4 (x - 3) + 10

x, 2 x^{2} y = 0

x^{2} + 6 b = 0

What are the solutions to the equation 5x^2+6x-4=0 ?
The solutions to the equation 5x^2+6x-4=0 are x=(-3+sqrt(29))/5 ,x=-(3+sqrt(29))/5
Find the zeros of 5x^2+6x-4=0
The zeros of 5x^2+6x-4=0 are x=(-3+sqrt(29))/5 ,x=-(3+sqrt(29))/5