What are the solutions to the equation 3x(x-2)-(x-6)=4(x-3)+10 ?

The solutions to the equation 3x(x-2)-(x-6)=4(x-3)+10 are x= 8/3 ,x=1

Find the zeros of 3x(x-2)-(x-6)=4(x-3)+10

The zeros of 3x(x-2)-(x-6)=4(x-3)+10 are x= 8/3 ,x=1

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

Popular >

3 x (x - 2) - (x - 6) = 4 (x - 3) + 10

x = \frac{8}{3}, x = 1

Decimal Notation

x = 2.66666 \dots, x = 1

Solution steps

3 x (x - 2) - (x - 6) = 4 (x - 3) + 10

Expand

3 x (x - 2) - (x - 6) : 3 x^{2} - 7 x + 6

Expand

4 (x - 3) + 10 : 4 x - 2

3 x^{2} - 7 x + 6 = 4 x - 2

Move

2

to the left side

3 x^{2} - 7 x + 8 = 4 x

Move

4 x

to the left side

3 x^{2} - 11 x + 8 = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- ( - 11 ) \pm ( - 11 ) ^{2} - 4 \cdot 3 \cdot 8}{2 \cdot 3}

(- 11)^{2} - 4 \cdot 3 \cdot 8 = 5

x_{1, 2} = \frac{- ( - 11 ) \pm 5}{2 \cdot 3}

Separate the solutions

x_{1} = \frac{- ( - 11 ) + 5}{2 \cdot 3}, x_{2} = \frac{- ( - 11 ) - 5}{2 \cdot 3}

x = \frac{- ( - 11 ) + 5}{2 \cdot 3} : \frac{8}{3}

x = \frac{- ( - 11 ) - 5}{2 \cdot 3} : 1

The solutions to the quadratic equation are:

x = \frac{8}{3}, x = 1

x, 2 x^{2} y = 0

x^{2} + 6 b = 0

9 x^{2} - 5 x = 4

x, y + x^{2} = 0

x, P (x - 3) = x^{2} + m x + 4

What are the solutions to the equation 3x(x-2)-(x-6)=4(x-3)+10 ?
The solutions to the equation 3x(x-2)-(x-6)=4(x-3)+10 are x= 8/3 ,x=1
Find the zeros of 3x(x-2)-(x-6)=4(x-3)+10
The zeros of 3x(x-2)-(x-6)=4(x-3)+10 are x= 8/3 ,x=1