What are the solutions to the equation 6^2+x^2=sqrt(97) ?

The solutions to the equation 6^2+x^2=sqrt(97) are x=sqrt(-\sqrt{97)+36}i,x=-sqrt(-\sqrt{97)+36}i

Find the zeros of 6^2+x^2=sqrt(97)

The zeros of 6^2+x^2=sqrt(97) are x=sqrt(-\sqrt{97)+36}i,x=-sqrt(-\sqrt{97)+36}i

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6^{2} + x^{2} = 97

x = - 97 + 36 i, x = - - 97 + 36 i

Solution steps

6^{2} + x^{2} = 97

Move

6^{2}

to the right side

x^{2} = 97 - 36

For

x^{2} = f (a)

the solutions are

x = f (a), - f (a)

x = 97 - 36, x = - 97 - 36

97 - 36 = - 97 + 36 i

- 97 - 36 = - - 97 + 36 i

x = - 97 + 36 i, x = - - 97 + 36 i

6 x - 0.4 x^{2} = 3.12

6 x^{2} + 12 x + 2 = - 10

12 x = 9 x^{2} + 4

x^{2} - 100 x + 900 = 0

2 x^{2} + 6 x - 56 = 0

What are the solutions to the equation 6^2+x^2=sqrt(97) ?
The solutions to the equation 6^2+x^2=sqrt(97) are x=sqrt(-\sqrt{97)+36}i,x=-sqrt(-\sqrt{97)+36}i
Find the zeros of 6^2+x^2=sqrt(97)
The zeros of 6^2+x^2=sqrt(97) are x=sqrt(-\sqrt{97)+36}i,x=-sqrt(-\sqrt{97)+36}i