What are the solutions to the equation 12x=9x^2+4 ?

The solutions to the equation 12x=9x^2+4 are x= 2/3

Find the zeros of 12x=9x^2+4

The zeros of 12x=9x^2+4 are x= 2/3

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12 x = 9 x^{2} + 4

x = \frac{2}{3}

Decimal Notation

x = 0.66666 \dots

Solution steps

12 x = 9 x^{2} + 4

Switch sides

9 x^{2} + 4 = 12 x

Move

12 x

to the left side

9 x^{2} + 4 - 12 x = 0

Write in the standard form

a x^{2} + b x + c = 0

9 x^{2} - 12 x + 4 = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- ( - 12 ) \pm ( - 12 ) ^{2} - 4 \cdot 9 \cdot 4}{2 \cdot 9}

(- 12)^{2} - 4 \cdot 9 \cdot 4 = 0

x_{1, 2} = \frac{- ( - 12 ) \pm 0}{2 \cdot 9}

x = \frac{- ( - 12 )}{2 \cdot 9}

\frac{- ( - 12 )}{2 \cdot 9} = \frac{2}{3}

x = \frac{2}{3}

The solution to the quadratic equation is:

x = \frac{2}{3}

x^{2} - 100 x + 900 = 0

2 x^{2} + 6 x - 56 = 0

10 q + 220 = - 0.05 q^{2} + 700

s^{2} + 0.1 s + 1 = 0

12 x^{2} - 8 x + 4 = 0

What are the solutions to the equation 12x=9x^2+4 ?
The solutions to the equation 12x=9x^2+4 are x= 2/3
Find the zeros of 12x=9x^2+4
The zeros of 12x=9x^2+4 are x= 2/3