What are the solutions to the equation 10q+220=-0.05q^2+700 ?

The solutions to the equation 10q+220=-0.05q^2+700 are q=-240,q=40

Find the zeros of 10q+220=-0.05q^2+700

The zeros of 10q+220=-0.05q^2+700 are q=-240,q=40

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10 q + 220 = - 0.05 q^{2} + 700

q = - 240, q = 40

Solution steps

10 q + 220 = - 0.05 q^{2} + 700

Multiply both sides by

100

1000 q + 22000 = - 5 q^{2} + 70000

Switch sides

- 5 q^{2} + 70000 = 1000 q + 22000

Move

22000

to the left side

- 5 q^{2} + 48000 = 1000 q

Move

1000 q

to the left side

- 5 q^{2} + 48000 - 1000 q = 0

Write in the standard form

a x^{2} + b x + c = 0

- 5 q^{2} - 1000 q + 48000 = 0

Solve with the quadratic formula

q_{1, 2} = \frac{- ( - 1000 ) \pm ( - 1000 ) ^{2} - 4 ( - 5 ) \cdot 48000}{2 ( - 5 )}

(- 1000)^{2} - 4 (- 5) \cdot 48000 = 1400

q_{1, 2} = \frac{- ( - 1000 ) \pm 1400}{2 ( - 5 )}

Separate the solutions

q_{1} = \frac{- ( - 1000 ) + 1400}{2 ( - 5 )}, q_{2} = \frac{- ( - 1000 ) - 1400}{2 ( - 5 )}

q = \frac{- ( - 1000 ) + 1400}{2 ( - 5 )} : - 240

q = \frac{- ( - 1000 ) - 1400}{2 ( - 5 )} : 40

The solutions to the quadratic equation are:

q = - 240, q = 40

s^{2} + 0.1 s + 1 = 0

12 x^{2} - 8 x + 4 = 0

3 x^{2} + 26 x + 2 = 0

4 x^{2} = - 4 x + 1

4 r^{2} - 5 r = 0

What are the solutions to the equation 10q+220=-0.05q^2+700 ?
The solutions to the equation 10q+220=-0.05q^2+700 are q=-240,q=40
Find the zeros of 10q+220=-0.05q^2+700
The zeros of 10q+220=-0.05q^2+700 are q=-240,q=40