What are the solutions to the equation 2x(3x+18)=30+12x ?

The solutions to the equation 2x(3x+18)=30+12x are x=1,x=-5

Find the zeros of 2x(3x+18)=30+12x

The zeros of 2x(3x+18)=30+12x are x=1,x=-5

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2 x (3 x + 18) = 30 + 12 x

x = 1, x = - 5

Solution steps

2 x (3 x + 18) = 30 + 12 x

Expand

2 x (3 x + 18) : 6 x^{2} + 36 x

6 x^{2} + 36 x = 30 + 12 x

Move

12 x

to the left side

6 x^{2} + 24 x = 30

Move

30

to the left side

6 x^{2} + 24 x - 30 = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- 24 \pm 2 4 ^{2} - 4 \cdot 6 ( - 30 )}{2 \cdot 6}

2 4^{2} - 4 \cdot 6 (- 30) = 36

x_{1, 2} = \frac{- 24 \pm 36}{2 \cdot 6}

Separate the solutions

x_{1} = \frac{- 24 + 36}{2 \cdot 6}, x_{2} = \frac{- 24 - 36}{2 \cdot 6}

x = \frac{- 24 + 36}{2 \cdot 6} : 1

x = \frac{- 24 - 36}{2 \cdot 6} : - 5

The solutions to the quadratic equation are:

x = 1, x = - 5

16 x^{2} = 8 x - 15

136 = (2 x + 6) (2 x + 15)

3902850 x^{2} - 6615000 x + 984760 = 0

x, x^{2} + x y^{2} + y^{2} = 1

6 x^{2} + 17 x - 39 = 0

What are the solutions to the equation 2x(3x+18)=30+12x ?
The solutions to the equation 2x(3x+18)=30+12x are x=1,x=-5
Find the zeros of 2x(3x+18)=30+12x
The zeros of 2x(3x+18)=30+12x are x=1,x=-5