What are the solutions to the equation 136=(2x+6)(2x+15) ?

The solutions to the equation 136=(2x+6)(2x+15) are x=1,x=-23/2

Find the zeros of 136=(2x+6)(2x+15)

The zeros of 136=(2x+6)(2x+15) are x=1,x=-23/2

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

Popular >

136 = (2 x + 6) (2 x + 15)

x = 1, x = - \frac{23}{2}

Decimal Notation

x = 1, x = - 11.5

Solution steps

136 = (2 x + 6) (2 x + 15)

Expand

(2 x + 6) (2 x + 15) : 4 x^{2} + 42 x + 90

136 = 4 x^{2} + 42 x + 90

Switch sides

4 x^{2} + 42 x + 90 = 136

Move

136

to the left side

4 x^{2} + 42 x - 46 = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- 42 \pm 4 2 ^{2} - 4 \cdot 4 ( - 46 )}{2 \cdot 4}

4 2^{2} - 4 \cdot 4 (- 46) = 50

x_{1, 2} = \frac{- 42 \pm 50}{2 \cdot 4}

Separate the solutions

x_{1} = \frac{- 42 + 50}{2 \cdot 4}, x_{2} = \frac{- 42 - 50}{2 \cdot 4}

x = \frac{- 42 + 50}{2 \cdot 4} : 1

x = \frac{- 42 - 50}{2 \cdot 4} : - \frac{23}{2}

The solutions to the quadratic equation are:

x = 1, x = - \frac{23}{2}

3902850 x^{2} - 6615000 x + 984760 = 0

x, x^{2} + x y^{2} + y^{2} = 1

6 x^{2} + 17 x - 39 = 0

- 3 x^{2} + 9 x + 30 = 0

2 x^{2} + 10 x = 28

What are the solutions to the equation 136=(2x+6)(2x+15) ?
The solutions to the equation 136=(2x+6)(2x+15) are x=1,x=-23/2
Find the zeros of 136=(2x+6)(2x+15)
The zeros of 136=(2x+6)(2x+15) are x=1,x=-23/2