What are the solutions to the equation 0.32q^2+37q-627=0 ?

The solutions to the equation 0.32q^2+37q-627=0 are q=15,q=-1045/8

Find the zeros of 0.32q^2+37q-627=0

The zeros of 0.32q^2+37q-627=0 are q=15,q=-1045/8

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0.32 q^{2} + 37 q - 627 = 0

q = 15, q = - \frac{1045}{8}

Decimal Notation

q = 15, q = - 130.625

Solution steps

0.32 q^{2} + 37 q - 627 = 0

Multiply both sides by

100

32 q^{2} + 3700 q - 62700 = 0

Solve with the quadratic formula

q_{1, 2} = \frac{- 3700 \pm 370 0 ^{2} - 4 \cdot 32 ( - 62700 )}{2 \cdot 32}

370 0^{2} - 4 \cdot 32 (- 62700) = 4660

q_{1, 2} = \frac{- 3700 \pm 4660}{2 \cdot 32}

Separate the solutions

q_{1} = \frac{- 3700 + 4660}{2 \cdot 32}, q_{2} = \frac{- 3700 - 4660}{2 \cdot 32}

q = \frac{- 3700 + 4660}{2 \cdot 32} : 15

q = \frac{- 3700 - 4660}{2 \cdot 32} : - \frac{1045}{8}

The solutions to the quadratic equation are:

q = 15, q = - \frac{1045}{8}

x^{2} - 1 = x - 1

y^{2} - 12 y + 52 = 0

\frac{2 x + 3}{6} \frac{4 x - 2}{9} = \frac{5}{3}

12 x^{2} - 5 x + 2 = 0

80 = x (\frac{x}{10} - 3) - 5 (\frac{x}{10} - 3)^{2}

What are the solutions to the equation 0.32q^2+37q-627=0 ?
The solutions to the equation 0.32q^2+37q-627=0 are q=15,q=-1045/8
Find the zeros of 0.32q^2+37q-627=0
The zeros of 0.32q^2+37q-627=0 are q=15,q=-1045/8