What are the solutions to the equation x^2+6x=79 ?

The solutions to the equation x^2+6x=79 are x=-3+2sqrt(22),x=-3-2sqrt(22)

Find the zeros of x^2+6x=79

The zeros of x^2+6x=79 are x=-3+2sqrt(22),x=-3-2sqrt(22)

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x^{2} + 6 x = 79

x = - 3 + 222, x = - 3 - 222

Decimal Notation

x = 6.38083 \dots, x = - 12.38083 \dots

Solution steps

x^{2} + 6 x = 79

Move

79

to the left side

x^{2} + 6 x - 79 = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- 6 \pm 6 ^{2} - 4 \cdot 1 \cdot ( - 79 )}{2 \cdot 1}

6^{2} - 4 \cdot 1 \cdot (- 79) = 422

x_{1, 2} = \frac{- 6 \pm 4 22}{2 \cdot 1}

Separate the solutions

x_{1} = \frac{- 6 + 4 22}{2 \cdot 1}, x_{2} = \frac{- 6 - 4 22}{2 \cdot 1}

x = \frac{- 6 + 4 22}{2 \cdot 1} : - 3 + 222

x = \frac{- 6 - 4 22}{2 \cdot 1} : - 3 - 222

The solutions to the quadratic equation are:

x = - 3 + 222, x = - 3 - 222

2 t^{2} - 14 t + 3 = 3

- 8 t + 21 = - t^{2}

m^{4} - 13 m^{2} + 36

e^{- 3 x} + 7 \geq 15

(5^{4})^{2}

What are the solutions to the equation x^2+6x=79 ?
The solutions to the equation x^2+6x=79 are x=-3+2sqrt(22),x=-3-2sqrt(22)
Find the zeros of x^2+6x=79
The zeros of x^2+6x=79 are x=-3+2sqrt(22),x=-3-2sqrt(22)