What are the solutions to the equation -x+x^2+1=0 ?

The solutions to the equation -x+x^2+1=0 are x= 1/2+i(sqrt(3))/2 ,x= 1/2-i(sqrt(3))/2

Find the zeros of -x+x^2+1=0

The zeros of -x+x^2+1=0 are x= 1/2+i(sqrt(3))/2 ,x= 1/2-i(sqrt(3))/2

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- x + x^{2} + 1 = 0

x = \frac{1}{2} + i \frac{3}{2}, x = \frac{1}{2} - i \frac{3}{2}

Solution steps

- x + x^{2} + 1 = 0

Write in the standard form

a x^{2} + b x + c = 0

x^{2} - x + 1 = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- ( - 1 ) \pm ( - 1 ) ^{2} - 4 \cdot 1 \cdot 1}{2 \cdot 1}

Simplify

(- 1)^{2} - 4 \cdot 1 \cdot 1 : 3 i

x_{1, 2} = \frac{- ( - 1 ) \pm 3 i}{2 \cdot 1}

Separate the solutions

x_{1} = \frac{- ( - 1 ) + 3 i}{2 \cdot 1}, x_{2} = \frac{- ( - 1 ) - 3 i}{2 \cdot 1}

x = \frac{- ( - 1 ) + 3 i}{2 \cdot 1} : \frac{1}{2} + i \frac{3}{2}

x = \frac{- ( - 1 ) - 3 i}{2 \cdot 1} : \frac{1}{2} - i \frac{3}{2}

The solutions to the quadratic equation are:

x = \frac{1}{2} + i \frac{3}{2}, x = \frac{1}{2} - i \frac{3}{2}

k, b (k d) (\frac{k d}{2}) = n A (d - k d)

x^{2} + 6 x + 19 = - 6

(m - 10)^{2} = - 20 m

0 = - \frac{4}{9} (x + 2)^{2} + 2

q^{2} + 8 q + 20 = 100 - 4 q - q^{2}

What are the solutions to the equation -x+x^2+1=0 ?
The solutions to the equation -x+x^2+1=0 are x= 1/2+i(sqrt(3))/2 ,x= 1/2-i(sqrt(3))/2
Find the zeros of -x+x^2+1=0
The zeros of -x+x^2+1=0 are x= 1/2+i(sqrt(3))/2 ,x= 1/2-i(sqrt(3))/2