What are the solutions to the equation 5x^2+12x+2=-5 ?

The solutions to the equation 5x^2+12x+2=-5 are x=-1,x=-7/5

Find the zeros of 5x^2+12x+2=-5

The zeros of 5x^2+12x+2=-5 are x=-1,x=-7/5

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5 x^{2} + 12 x + 2 = - 5

x = - 1, x = - \frac{7}{5}

Decimal Notation

x = - 1, x = - 1.4

Solution steps

5 x^{2} + 12 x + 2 = - 5

Move

5

to the left side

5 x^{2} + 12 x + 7 = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- 12 \pm 1 2 ^{2} - 4 \cdot 5 \cdot 7}{2 \cdot 5}

1 2^{2} - 4 \cdot 5 \cdot 7 = 2

x_{1, 2} = \frac{- 12 \pm 2}{2 \cdot 5}

Separate the solutions

x_{1} = \frac{- 12 + 2}{2 \cdot 5}, x_{2} = \frac{- 12 - 2}{2 \cdot 5}

x = \frac{- 12 + 2}{2 \cdot 5} : - 1

x = \frac{- 12 - 2}{2 \cdot 5} : - \frac{7}{5}

The solutions to the quadratic equation are:

x = - 1, x = - \frac{7}{5}

x, x^{2} + y^{2} - y + z^{2} = 0

X^{2} + 3 X = 0

c^{2} = 1 8^{2} + 8 0^{2}

x (x - 7) = - 12

x^{2} - 58 x + 741 = 0

What are the solutions to the equation 5x^2+12x+2=-5 ?
The solutions to the equation 5x^2+12x+2=-5 are x=-1,x=-7/5
Find the zeros of 5x^2+12x+2=-5
The zeros of 5x^2+12x+2=-5 are x=-1,x=-7/5