What are the solutions to the equation x(x-7)=-12 ?

The solutions to the equation x(x-7)=-12 are x=4,x=3

Find the zeros of x(x-7)=-12

The zeros of x(x-7)=-12 are x=4,x=3

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x (x - 7) = - 12

x = 4, x = 3

Solution steps

x (x - 7) = - 12

Expand

x (x - 7) : x^{2} - 7 x

x^{2} - 7 x = - 12

Move

12

to the left side

x^{2} - 7 x + 12 = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- ( - 7 ) \pm ( - 7 ) ^{2} - 4 \cdot 1 \cdot 12}{2 \cdot 1}

(- 7)^{2} - 4 \cdot 1 \cdot 12 = 1

x_{1, 2} = \frac{- ( - 7 ) \pm 1}{2 \cdot 1}

Separate the solutions

x_{1} = \frac{- ( - 7 ) + 1}{2 \cdot 1}, x_{2} = \frac{- ( - 7 ) - 1}{2 \cdot 1}

x = \frac{- ( - 7 ) + 1}{2 \cdot 1} : 4

x = \frac{- ( - 7 ) - 1}{2 \cdot 1} : 3

The solutions to the quadratic equation are:

x = 4, x = 3

x^{2} - 58 x + 741 = 0

- 3 x^{2} + 17 x = 0

x^{2} - (23 + 1) x + 23 = 0

3 x^{2} + 18 x - 9 = 0

\frac{m ^{2}}{5} - \frac{m}{2} = \frac{3}{10}

What are the solutions to the equation x(x-7)=-12 ?
The solutions to the equation x(x-7)=-12 are x=4,x=3
Find the zeros of x(x-7)=-12
The zeros of x(x-7)=-12 are x=4,x=3