What are the solutions to the equation 3x^2+18x-9=0 ?

The solutions to the equation 3x^2+18x-9=0 are x=-3+2sqrt(3),x=-3-2sqrt(3)

Find the zeros of 3x^2+18x-9=0

The zeros of 3x^2+18x-9=0 are x=-3+2sqrt(3),x=-3-2sqrt(3)

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3 x^{2} + 18 x - 9 = 0

x = - 3 + 23, x = - 3 - 23

Decimal Notation

x = 0.46410 \dots, x = - 6.46410 \dots

Solution steps

3 x^{2} + 18 x - 9 = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- 18 \pm 1 8 ^{2} - 4 \cdot 3 ( - 9 )}{2 \cdot 3}

1 8^{2} - 4 \cdot 3 (- 9) = 123

x_{1, 2} = \frac{- 18 \pm 12 3}{2 \cdot 3}

Separate the solutions

x_{1} = \frac{- 18 + 12 3}{2 \cdot 3}, x_{2} = \frac{- 18 - 12 3}{2 \cdot 3}

x = \frac{- 18 + 12 3}{2 \cdot 3} : - 3 + 23

x = \frac{- 18 - 12 3}{2 \cdot 3} : - 3 - 23

The solutions to the quadratic equation are:

x = - 3 + 23, x = - 3 - 23

\frac{m ^{2}}{5} - \frac{m}{2} = \frac{3}{10}

(x + 3) (x - 3) - (x - 2)^{2} = 6 + x (x - 5)

- 3 l^{2} + 20 l + 100 = 0

3 (x^{2} - 2 x) = 8 (x - 2) + 8

x^{2} - 11 x - 350 = 0

What are the solutions to the equation 3x^2+18x-9=0 ?
The solutions to the equation 3x^2+18x-9=0 are x=-3+2sqrt(3),x=-3-2sqrt(3)
Find the zeros of 3x^2+18x-9=0
The zeros of 3x^2+18x-9=0 are x=-3+2sqrt(3),x=-3-2sqrt(3)