What are the solutions to the equation 0= 1/4 (8x-x^2) ?

The solutions to the equation 0= 1/4 (8x-x^2) are x=0,x=8

Find the zeros of 0= 1/4 (8x-x^2)

The zeros of 0= 1/4 (8x-x^2) are x=0,x=8

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0 = \frac{1}{4} (8 x - x^{2})

x = 0, x = 8

Solution steps

0 = \frac{1}{4} (8 x - x^{2})

Multiply both sides by

4

0 = 8 x - x^{2}

Switch sides

8 x - x^{2} = 0

Write in the standard form

a x^{2} + b x + c = 0

- x^{2} + 8 x = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- 8 \pm 8 ^{2} - 4 ( - 1 ) \cdot 0}{2 ( - 1 )}

8^{2} - 4 (- 1) \cdot 0 = 8

x_{1, 2} = \frac{- 8 \pm 8}{2 ( - 1 )}

Separate the solutions

x_{1} = \frac{- 8 + 8}{2 ( - 1 )}, x_{2} = \frac{- 8 - 8}{2 ( - 1 )}

x = \frac{- 8 + 8}{2 ( - 1 )} : 0

x = \frac{- 8 - 8}{2 ( - 1 )} : 8

The solutions to the quadratic equation are:

x = 0, x = 8

x^{2} + 3 x + 2 = 0

4 - d \cdot [4 - d + d] \cdot [4 - d + 2 d] = 16

x, m^{2} x^{2} + y^{2} = b^{2}

x, x^{2} + y^{2} - 2 (2 x + 3 y) + 14 = 0

- (x - 3) = (x - \frac{7}{2}) (x + \frac{3}{4})

What are the solutions to the equation 0= 1/4 (8x-x^2) ?
The solutions to the equation 0= 1/4 (8x-x^2) are x=0,x=8
Find the zeros of 0= 1/4 (8x-x^2)
The zeros of 0= 1/4 (8x-x^2) are x=0,x=8