What are the solutions to the equation 9x^2-50x+57=0 ?

The solutions to the equation 9x^2-50x+57=0 are x=(25+4sqrt(7))/9 ,x=(25-4sqrt(7))/9

Find the zeros of 9x^2-50x+57=0

The zeros of 9x^2-50x+57=0 are x=(25+4sqrt(7))/9 ,x=(25-4sqrt(7))/9

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9 x^{2} - 50 x + 57 = 0

x = \frac{25 + 4 7}{9}, x = \frac{25 - 4 7}{9}

Decimal Notation

x = 3.95366 \dots, x = 1.60188 \dots

Solution steps

9 x^{2} - 50 x + 57 = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- ( - 50 ) \pm ( - 50 ) ^{2} - 4 \cdot 9 \cdot 57}{2 \cdot 9}

(- 50)^{2} - 4 \cdot 9 \cdot 57 = 87

x_{1, 2} = \frac{- ( - 50 ) \pm 8 7}{2 \cdot 9}

Separate the solutions

x_{1} = \frac{- ( - 50 ) + 8 7}{2 \cdot 9}, x_{2} = \frac{- ( - 50 ) - 8 7}{2 \cdot 9}

x = \frac{- ( - 50 ) + 8 7}{2 \cdot 9} : \frac{25 + 4 7}{9}

x = \frac{- ( - 50 ) - 8 7}{2 \cdot 9} : \frac{25 - 4 7}{9}

The solutions to the quadratic equation are:

x = \frac{25 + 4 7}{9}, x = \frac{25 - 4 7}{9}

- x^{2} + 1 = x - 1

- 10 z^{2} - 5 z = 0

7 x^{2} - 5 x + 6 = - 8

x^{2} + x = 0.75

2^{2} + y^{2} - 6 y - 16 = 0

What are the solutions to the equation 9x^2-50x+57=0 ?
The solutions to the equation 9x^2-50x+57=0 are x=(25+4sqrt(7))/9 ,x=(25-4sqrt(7))/9
Find the zeros of 9x^2-50x+57=0
The zeros of 9x^2-50x+57=0 are x=(25+4sqrt(7))/9 ,x=(25-4sqrt(7))/9