What are the solutions to the equation 7^2=x^2+5^2 ?

The solutions to the equation 7^2=x^2+5^2 are x=2sqrt(6),x=-2sqrt(6)

Find the zeros of 7^2=x^2+5^2

The zeros of 7^2=x^2+5^2 are x=2sqrt(6),x=-2sqrt(6)

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7^{2} = x^{2} + 5^{2}

x = 26, x = - 26

Decimal Notation

x = 4.89897 \dots, x = - 4.89897 \dots

Solution steps

7^{2} = x^{2} + 5^{2}

Switch sides

x^{2} + 5^{2} = 7^{2}

Move

5^{2}

to the right side

x^{2} = 24

For

x^{2} = f (a)

the solutions are

x = f (a), - f (a)

x = 24, x = - 24

24 = 26

- 24 = - 26

x = 26, x = - 26

x^{2} = 5 x

x^{2} - 6 x = 4 x - 2 x^{2} + 25

\frac{1}{2} x + 2 = x^{2} + \frac{1}{2} x - 14

s^{2} - 1.16 s - 0.51 = 0

100 = 4 π + r^{2}

What are the solutions to the equation 7^2=x^2+5^2 ?
The solutions to the equation 7^2=x^2+5^2 are x=2sqrt(6),x=-2sqrt(6)
Find the zeros of 7^2=x^2+5^2
The zeros of 7^2=x^2+5^2 are x=2sqrt(6),x=-2sqrt(6)