What are the solutions to the equation 100=4pi+r^2 ?

The solutions to the equation 100=4pi+r^2 are r=sqrt(100-4pi),r=-sqrt(100-4pi)

Find the zeros of 100=4pi+r^2

The zeros of 100=4pi+r^2 are r=sqrt(100-4pi),r=-sqrt(100-4pi)

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100 = 4 π + r^{2}

r = 100 - 4 π, r = - 100 - 4 π

Decimal Notation

r = 9.35059 \dots, r = - 9.35059 \dots

Solution steps

100 = 4 π + r^{2}

Switch sides

4 π + r^{2} = 100

Move

4 π

to the right side

r^{2} = 100 - 4 π

For

x^{2} = f (a)

the solutions are

x = f (a), - f (a)

r = 100 - 4 π, r = - 100 - 4 π

3 n^{2} + n - 50 = n + 97

- 3 k^{2} = - 12

2 x^{2} - 11 x + 11 = 0

24 x^{2} - 2 x - 15 = 0

- x^{2} - 5 x - 10 = 0

What are the solutions to the equation 100=4pi+r^2 ?
The solutions to the equation 100=4pi+r^2 are r=sqrt(100-4pi),r=-sqrt(100-4pi)
Find the zeros of 100=4pi+r^2
The zeros of 100=4pi+r^2 are r=sqrt(100-4pi),r=-sqrt(100-4pi)