What are the solutions to the equation 3n^2+n-50=n+97 ?

The solutions to the equation 3n^2+n-50=n+97 are n=7,n=-7

Find the zeros of 3n^2+n-50=n+97

The zeros of 3n^2+n-50=n+97 are n=7,n=-7

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3 n^{2} + n - 50 = n + 97

n = 7, n = - 7

Solution steps

3 n^{2} + n - 50 = n + 97

Move

50

to the right side

3 n^{2} + n = n + 147

Move

n

to the left side

3 n^{2} = 147

Divide both sides by

3

n^{2} = 49

For

x^{2} = f (a)

the solutions are

x = f (a), - f (a)

n = 49, n = - 49

49 = 7

- 49 = - 7

n = 7, n = - 7

- 3 k^{2} = - 12

2 x^{2} - 11 x + 11 = 0

24 x^{2} - 2 x - 15 = 0

- x^{2} - 5 x - 10 = 0

x^{2} + \frac{7}{2} x - 2 = 0

What are the solutions to the equation 3n^2+n-50=n+97 ?
The solutions to the equation 3n^2+n-50=n+97 are n=7,n=-7
Find the zeros of 3n^2+n-50=n+97
The zeros of 3n^2+n-50=n+97 are n=7,n=-7