What are the solutions to the equation 2x^2-11x+11=0 ?

The solutions to the equation 2x^2-11x+11=0 are x=(11+sqrt(33))/4 ,x=(11-sqrt(33))/4

Find the zeros of 2x^2-11x+11=0

The zeros of 2x^2-11x+11=0 are x=(11+sqrt(33))/4 ,x=(11-sqrt(33))/4

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2 x^{2} - 11 x + 11 = 0

x = \frac{11 + 33}{4}, x = \frac{11 - 33}{4}

Decimal Notation

x = 4.18614 \dots, x = 1.31385 \dots

Solution steps

2 x^{2} - 11 x + 11 = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- ( - 11 ) \pm ( - 11 ) ^{2} - 4 \cdot 2 \cdot 11}{2 \cdot 2}

(- 11)^{2} - 4 \cdot 2 \cdot 11 = 33

x_{1, 2} = \frac{- ( - 11 ) \pm 33}{2 \cdot 2}

Separate the solutions

x_{1} = \frac{- ( - 11 ) + 33}{2 \cdot 2}, x_{2} = \frac{- ( - 11 ) - 33}{2 \cdot 2}

x = \frac{- ( - 11 ) + 33}{2 \cdot 2} : \frac{11 + 33}{4}

x = \frac{- ( - 11 ) - 33}{2 \cdot 2} : \frac{11 - 33}{4}

The solutions to the quadratic equation are:

x = \frac{11 + 33}{4}, x = \frac{11 - 33}{4}

24 x^{2} - 2 x - 15 = 0

- x^{2} - 5 x - 10 = 0

x^{2} + \frac{7}{2} x - 2 = 0

(2 x + 3) \cdot (2 x - 3) = 135

0 = 1 - 3 x^{2}

What are the solutions to the equation 2x^2-11x+11=0 ?
The solutions to the equation 2x^2-11x+11=0 are x=(11+sqrt(33))/4 ,x=(11-sqrt(33))/4
Find the zeros of 2x^2-11x+11=0
The zeros of 2x^2-11x+11=0 are x=(11+sqrt(33))/4 ,x=(11-sqrt(33))/4