What are the solutions to the equation (2x+3)*(2x-3)=135 ?

The solutions to the equation (2x+3)*(2x-3)=135 are x=6,x=-6

Find the zeros of (2x+3)*(2x-3)=135

The zeros of (2x+3)*(2x-3)=135 are x=6,x=-6

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(2 x + 3) \cdot (2 x - 3) = 135

x = 6, x = - 6

Solution steps

(2 x + 3) (2 x - 3) = 135

Expand

(2 x + 3) (2 x - 3) : 4 x^{2} - 9

4 x^{2} - 9 = 135

Move

135

to the left side

4 x^{2} - 144 = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- 0 \pm 0 ^{2} - 4 \cdot 4 ( - 144 )}{2 \cdot 4}

0^{2} - 4 \cdot 4 (- 144) = 48

x_{1, 2} = \frac{- 0 \pm 48}{2 \cdot 4}

Separate the solutions

x_{1} = \frac{- 0 + 48}{2 \cdot 4}, x_{2} = \frac{- 0 - 48}{2 \cdot 4}

x = \frac{- 0 + 48}{2 \cdot 4} : 6

x = \frac{- 0 - 48}{2 \cdot 4} : - 6

The solutions to the quadratic equation are:

x = 6, x = - 6

0 = 1 - 3 x^{2}

x^{2} - 37 = 188

2 k^{2} + 5 k + 3 = 0

\frac{5 - x}{6000} = \frac{1}{2} \cdot 0.001 \cdot (x - 1)^{2}

2 x^{2} + 11 = x^{2} + 12

What are the solutions to the equation (2x+3)*(2x-3)=135 ?
The solutions to the equation (2x+3)*(2x-3)=135 are x=6,x=-6
Find the zeros of (2x+3)*(2x-3)=135
The zeros of (2x+3)*(2x-3)=135 are x=6,x=-6