What are the solutions to the equation (x-3)(x+5)+6=2x+7 ?

The solutions to the equation (x-3)(x+5)+6=2x+7 are x=4,x=-4

Find the zeros of (x-3)(x+5)+6=2x+7

The zeros of (x-3)(x+5)+6=2x+7 are x=4,x=-4

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(x - 3) (x + 5) + 6 = 2 x + 7

x = 4, x = - 4

Solution steps

(x - 3) (x + 5) + 6 = 2 x + 7

Expand

(x - 3) (x + 5) + 6 : x^{2} + 2 x - 9

x^{2} + 2 x - 9 = 2 x + 7

Move

9

to the right side

x^{2} + 2 x = 2 x + 16

Move

2 x

to the left side

x^{2} = 16

For

x^{2} = f (a)

the solutions are

x = f (a), - f (a)

x = 16, x = - 16

16 = 4

- 16 = - 4

x = 4, x = - 4

- 0.01 x^{2} - 0.2 x + 8 = 0.01 x^{2} + 0.1 x + 3

2 x^{2} + 13 x - 32 = 0

0.233 = - 6 (1 0^{- 5}) x^{2} + 0.0132 x

x = - 0.00075 (5 - 15 + 3 - x \cdot 100)^{2}

16 x - 32 = 9 x^{2} + 18 x + 9

What are the solutions to the equation (x-3)(x+5)+6=2x+7 ?
The solutions to the equation (x-3)(x+5)+6=2x+7 are x=4,x=-4
Find the zeros of (x-3)(x+5)+6=2x+7
The zeros of (x-3)(x+5)+6=2x+7 are x=4,x=-4