What are the solutions to the equation -x^2-12=-8x ?

The solutions to the equation -x^2-12=-8x are x=2,x=6

Find the zeros of -x^2-12=-8x

The zeros of -x^2-12=-8x are x=2,x=6

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- x^{2} - 12 = - 8 x

x = 2, x = 6

Solution steps

- x^{2} - 12 = - 8 x

Move

8 x

to the left side

- x^{2} - 12 + 8 x = 0

Write in the standard form

a x^{2} + b x + c = 0

- x^{2} + 8 x - 12 = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- 8 \pm 8 ^{2} - 4 ( - 1 ) ( - 12 )}{2 ( - 1 )}

8^{2} - 4 (- 1) (- 12) = 4

x_{1, 2} = \frac{- 8 \pm 4}{2 ( - 1 )}

Separate the solutions

x_{1} = \frac{- 8 + 4}{2 ( - 1 )}, x_{2} = \frac{- 8 - 4}{2 ( - 1 )}

x = \frac{- 8 + 4}{2 ( - 1 )} : 2

x = \frac{- 8 - 4}{2 ( - 1 )} : 6

The solutions to the quadratic equation are:

x = 2, x = 6

43575 - 75 xx = 4275

3 x^{2} - 2 x - 14 = 2

x^{2} - 30 x + 2 = 0

x^{2} = 8^{2} + 1 6^{2}

n^{2} - 13 n + 24 = 0

What are the solutions to the equation -x^2-12=-8x ?
The solutions to the equation -x^2-12=-8x are x=2,x=6
Find the zeros of -x^2-12=-8x
The zeros of -x^2-12=-8x are x=2,x=6