What are the solutions to the equation n^2-13n+24=0 ?

The solutions to the equation n^2-13n+24=0 are n=(13+sqrt(73))/2 ,n=(13-sqrt(73))/2

Find the zeros of n^2-13n+24=0

The zeros of n^2-13n+24=0 are n=(13+sqrt(73))/2 ,n=(13-sqrt(73))/2

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n^{2} - 13 n + 24 = 0

n = \frac{13 + 73}{2}, n = \frac{13 - 73}{2}

Decimal Notation

n = 10.77200 \dots, n = 2.22799 \dots

Solution steps

n^{2} - 13 n + 24 = 0

Solve with the quadratic formula

n_{1, 2} = \frac{- ( - 13 ) \pm ( - 13 ) ^{2} - 4 \cdot 1 \cdot 24}{2 \cdot 1}

(- 13)^{2} - 4 \cdot 1 \cdot 24 = 73

n_{1, 2} = \frac{- ( - 13 ) \pm 73}{2 \cdot 1}

Separate the solutions

n_{1} = \frac{- ( - 13 ) + 73}{2 \cdot 1}, n_{2} = \frac{- ( - 13 ) - 73}{2 \cdot 1}

n = \frac{- ( - 13 ) + 73}{2 \cdot 1} : \frac{13 + 73}{2}

n = \frac{- ( - 13 ) - 73}{2 \cdot 1} : \frac{13 - 73}{2}

The solutions to the quadratic equation are:

n = \frac{13 + 73}{2}, n = \frac{13 - 73}{2}

5 x^{2} + 4 = 3 x + 9

2 x^{2} + 15 x - 11 = - 3

2 x^{2} + 4 = 16

x^{2} - 1.5 x - 1 = 0

6 x^{2} = 10 - 11 x

What are the solutions to the equation n^2-13n+24=0 ?
The solutions to the equation n^2-13n+24=0 are n=(13+sqrt(73))/2 ,n=(13-sqrt(73))/2
Find the zeros of n^2-13n+24=0
The zeros of n^2-13n+24=0 are n=(13+sqrt(73))/2 ,n=(13-sqrt(73))/2