What are the solutions to the equation 2x^2+15x-11=-3 ?

The solutions to the equation 2x^2+15x-11=-3 are x= 1/2 ,x=-8

Find the zeros of 2x^2+15x-11=-3

The zeros of 2x^2+15x-11=-3 are x= 1/2 ,x=-8

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2 x^{2} + 15 x - 11 = - 3

x = \frac{1}{2}, x = - 8

Decimal Notation

x = 0.5, x = - 8

Solution steps

2 x^{2} + 15 x - 11 = - 3

Move

3

to the left side

2 x^{2} + 15 x - 8 = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- 15 \pm 1 5 ^{2} - 4 \cdot 2 ( - 8 )}{2 \cdot 2}

1 5^{2} - 4 \cdot 2 (- 8) = 17

x_{1, 2} = \frac{- 15 \pm 17}{2 \cdot 2}

Separate the solutions

x_{1} = \frac{- 15 + 17}{2 \cdot 2}, x_{2} = \frac{- 15 - 17}{2 \cdot 2}

x = \frac{- 15 + 17}{2 \cdot 2} : \frac{1}{2}

x = \frac{- 15 - 17}{2 \cdot 2} : - 8

The solutions to the quadratic equation are:

x = \frac{1}{2}, x = - 8

2 x^{2} + 4 = 16

x^{2} - 1.5 x - 1 = 0

6 x^{2} = 10 - 11 x

6 n^{2} - 18 n - 18 = 6

x, x^{2} + x y - y^{2} = 0

What are the solutions to the equation 2x^2+15x-11=-3 ?
The solutions to the equation 2x^2+15x-11=-3 are x= 1/2 ,x=-8
Find the zeros of 2x^2+15x-11=-3
The zeros of 2x^2+15x-11=-3 are x= 1/2 ,x=-8