What are the solutions to the equation x^2-1.5x-1=0 ?

The solutions to the equation x^2-1.5x-1=0 are x=2,x=-1/2

Find the zeros of x^2-1.5x-1=0

The zeros of x^2-1.5x-1=0 are x=2,x=-1/2

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x^{2} - 1.5 x - 1 = 0

x = 2, x = - \frac{1}{2}

Decimal Notation

x = 2, x = - 0.5

Solution steps

x^{2} - 1.5 x - 1 = 0

Multiply both sides by

10

10 x^{2} - 15 x - 10 = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- ( - 15 ) \pm ( - 15 ) ^{2} - 4 \cdot 10 ( - 10 )}{2 \cdot 10}

(- 15)^{2} - 4 \cdot 10 (- 10) = 25

x_{1, 2} = \frac{- ( - 15 ) \pm 25}{2 \cdot 10}

Separate the solutions

x_{1} = \frac{- ( - 15 ) + 25}{2 \cdot 10}, x_{2} = \frac{- ( - 15 ) - 25}{2 \cdot 10}

x = \frac{- ( - 15 ) + 25}{2 \cdot 10} : 2

x = \frac{- ( - 15 ) - 25}{2 \cdot 10} : - \frac{1}{2}

The solutions to the quadratic equation are:

x = 2, x = - \frac{1}{2}

6 x^{2} = 10 - 11 x

6 n^{2} - 18 n - 18 = 6

x, x^{2} + x y - y^{2} = 0

x e x - 2 = 0

20 x^{2} + 56 x + 15 = 0

What are the solutions to the equation x^2-1.5x-1=0 ?
The solutions to the equation x^2-1.5x-1=0 are x=2,x=-1/2
Find the zeros of x^2-1.5x-1=0
The zeros of x^2-1.5x-1=0 are x=2,x=-1/2