What are the solutions to the equation solvefor x,x^2-4x-30=-2x+33 ?

The solutions to the equation solvefor x,x^2-4x-30=-2x+33 are x=9,x=-7

Find the zeros of solvefor x,x^2-4x-30=-2x+33

The zeros of solvefor x,x^2-4x-30=-2x+33 are x=9,x=-7

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x, x^{2} - 4 x - 30 = - 2 x + 33

x = 9, x = - 7

Solution steps

x^{2} - 4 x - 30 = - 2 x + 33

Move

33

to the left side

x^{2} - 4 x - 63 = - 2 x

Move

2 x

to the left side

x^{2} - 2 x - 63 = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- ( - 2 ) \pm ( - 2 ) ^{2} - 4 \cdot 1 \cdot ( - 63 )}{2 \cdot 1}

(- 2)^{2} - 4 \cdot 1 \cdot (- 63) = 16

x_{1, 2} = \frac{- ( - 2 ) \pm 16}{2 \cdot 1}

Separate the solutions

x_{1} = \frac{- ( - 2 ) + 16}{2 \cdot 1}, x_{2} = \frac{- ( - 2 ) - 16}{2 \cdot 1}

x = \frac{- ( - 2 ) + 16}{2 \cdot 1} : 9

x = \frac{- ( - 2 ) - 16}{2 \cdot 1} : - 7

The solutions to the quadratic equation are:

x = 9, x = - 7

x, 3 (x - 4)^{2} = 5 x^{2}

7 x^{2} + 29 x + 4 = 0

x^{2} - 2 x - 27 = 0

2 x^{2} + 10 x + 25 = 0

x^{2} + 4 x - 40 = 10 x + 15

What are the solutions to the equation solvefor x,x^2-4x-30=-2x+33 ?
The solutions to the equation solvefor x,x^2-4x-30=-2x+33 are x=9,x=-7
Find the zeros of solvefor x,x^2-4x-30=-2x+33
The zeros of solvefor x,x^2-4x-30=-2x+33 are x=9,x=-7