What are the solutions to the equation 10b^2=27b-18 ?

The solutions to the equation 10b^2=27b-18 are b= 3/2 ,b= 6/5

Find the zeros of 10b^2=27b-18

The zeros of 10b^2=27b-18 are b= 3/2 ,b= 6/5

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10 b^{2} = 27 b - 18

b = \frac{3}{2}, b = \frac{6}{5}

Decimal Notation

b = 1.5, b = 1.2

Solution steps

10 b^{2} = 27 b - 18

Move

18

to the left side

10 b^{2} + 18 = 27 b

Move

27 b

to the left side

10 b^{2} + 18 - 27 b = 0

Write in the standard form

a x^{2} + b x + c = 0

10 b^{2} - 27 b + 18 = 0

Solve with the quadratic formula

b_{1, 2} = \frac{- ( - 27 ) \pm ( - 27 ) ^{2} - 4 \cdot 10 \cdot 18}{2 \cdot 10}

(- 27)^{2} - 4 \cdot 10 \cdot 18 = 3

b_{1, 2} = \frac{- ( - 27 ) \pm 3}{2 \cdot 10}

Separate the solutions

b_{1} = \frac{- ( - 27 ) + 3}{2 \cdot 10}, b_{2} = \frac{- ( - 27 ) - 3}{2 \cdot 10}

b = \frac{- ( - 27 ) + 3}{2 \cdot 10} : \frac{3}{2}

b = \frac{- ( - 27 ) - 3}{2 \cdot 10} : \frac{6}{5}

The solutions to the quadratic equation are:

b = \frac{3}{2}, b = \frac{6}{5}

5 x^{3} - 20 x

2 ∣ 7 - x ∣ + 4 > 1

\frac{x ^{2} - 6 x - 16}{x ^{2} - x - 6} \leq 0

x (x + 1) = 2070

\frac{1}{6} x + 6 + 2 < 3

What are the solutions to the equation 10b^2=27b-18 ?
The solutions to the equation 10b^2=27b-18 are b= 3/2 ,b= 6/5
Find the zeros of 10b^2=27b-18
The zeros of 10b^2=27b-18 are b= 3/2 ,b= 6/5