What are the solutions to the equation 20^2+7^2=x^2 ?

The solutions to the equation 20^2+7^2=x^2 are x=sqrt(449),x=-sqrt(449)

Find the zeros of 20^2+7^2=x^2

The zeros of 20^2+7^2=x^2 are x=sqrt(449),x=-sqrt(449)

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2 0^{2} + 7^{2} = x^{2}

x = 449, x = - 449

Decimal Notation

x = 21.18962 \dots, x = - 21.18962 \dots

Solution steps

2 0^{2} + 7^{2} = x^{2}

Switch sides

x^{2} = 2 0^{2} + 7^{2}

Simplify

2 0^{2} + 7^{2} : 449

For

x^{2} = f (a)

the solutions are

x = f (a), - f (a)

x = 449, x = - 449

t, e = e_{0} + v_{0} \cdot t + \frac{1}{2} \cdot a t^{2}

y, x^{2} + (y - 1)^{2} = 4

x, 2 x^{2} - 5 x y - 3 y^{2} = 0

n (x) = (x - 2)^{2} - 3

6 a^{2} + 22 a - 8 = 0

What are the solutions to the equation 20^2+7^2=x^2 ?
The solutions to the equation 20^2+7^2=x^2 are x=sqrt(449),x=-sqrt(449)
Find the zeros of 20^2+7^2=x^2
The zeros of 20^2+7^2=x^2 are x=sqrt(449),x=-sqrt(449)