What are the solutions to the equation solvefor y,x^2+(y-1)^2=4 ?

The solutions to the equation solvefor y,x^2+(y-1)^2=4 are y=sqrt(4-x^2)+1,y=-sqrt(4-x^2)+1

Find the zeros of solvefor y,x^2+(y-1)^2=4

The zeros of solvefor y,x^2+(y-1)^2=4 are y=sqrt(4-x^2)+1,y=-sqrt(4-x^2)+1

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solve for

y, x^{2} + (y - 1)^{2} = 4

y = 4 - x^{2} + 1, y = - 4 - x^{2} + 1

Solution steps

x^{2} + (y - 1)^{2} = 4

Move

x^{2}

to the right side

(y - 1)^{2} = 4 - x^{2}

For

(g (x))^{2} = f (a)

the solutions are

g (x) = f (a), - f (a)

Solve

y - 1 = 4 - x^{2} : y = 4 - x^{2} + 1

Solve

y - 1 = - 4 - x^{2} : y = - 4 - x^{2} + 1

The solutions to the quadratic equation are:

y = 4 - x^{2} + 1, y = - 4 - x^{2} + 1

x, 2 x^{2} - 5 x y - 3 y^{2} = 0

n (x) = (x - 2)^{2} - 3

6 a^{2} + 22 a - 8 = 0

4 x^{2} + x = 4

6 x^{2} - 5 x = 4

What are the solutions to the equation solvefor y,x^2+(y-1)^2=4 ?
The solutions to the equation solvefor y,x^2+(y-1)^2=4 are y=sqrt(4-x^2)+1,y=-sqrt(4-x^2)+1
Find the zeros of solvefor y,x^2+(y-1)^2=4
The zeros of solvefor y,x^2+(y-1)^2=4 are y=sqrt(4-x^2)+1,y=-sqrt(4-x^2)+1