What are the solutions to the equation 6x^2-5x=4 ?

The solutions to the equation 6x^2-5x=4 are x= 4/3 ,x=-1/2

Find the zeros of 6x^2-5x=4

The zeros of 6x^2-5x=4 are x= 4/3 ,x=-1/2

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6 x^{2} - 5 x = 4

x = \frac{4}{3}, x = - \frac{1}{2}

Decimal Notation

x = 1.33333 \dots, x = - 0.5

Solution steps

6 x^{2} - 5 x = 4

Move

4

to the left side

6 x^{2} - 5 x - 4 = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- ( - 5 ) \pm ( - 5 ) ^{2} - 4 \cdot 6 ( - 4 )}{2 \cdot 6}

(- 5)^{2} - 4 \cdot 6 (- 4) = 11

x_{1, 2} = \frac{- ( - 5 ) \pm 11}{2 \cdot 6}

Separate the solutions

x_{1} = \frac{- ( - 5 ) + 11}{2 \cdot 6}, x_{2} = \frac{- ( - 5 ) - 11}{2 \cdot 6}

x = \frac{- ( - 5 ) + 11}{2 \cdot 6} : \frac{4}{3}

x = \frac{- ( - 5 ) - 11}{2 \cdot 6} : - \frac{1}{2}

The solutions to the quadratic equation are:

x = \frac{4}{3}, x = - \frac{1}{2}

0.05 x^{2} + 10 x - 480 = 0

(x + 1)^{2} - (2 x + 3)^{2} = 0

3 x + 6 = (x + 4)^{2} - 10

12 x^{2} + 32 x - 64 = 0

8 - t^{2} = 0

What are the solutions to the equation 6x^2-5x=4 ?
The solutions to the equation 6x^2-5x=4 are x= 4/3 ,x=-1/2
Find the zeros of 6x^2-5x=4
The zeros of 6x^2-5x=4 are x= 4/3 ,x=-1/2