What are the solutions to the equation 0.05x^2+10x-480=0 ?

The solutions to the equation 0.05x^2+10x-480=0 are x=40,x=-240

Find the zeros of 0.05x^2+10x-480=0

The zeros of 0.05x^2+10x-480=0 are x=40,x=-240

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0.05 x^{2} + 10 x - 480 = 0

x = 40, x = - 240

Solution steps

0.05 x^{2} + 10 x - 480 = 0

Multiply both sides by

100

5 x^{2} + 1000 x - 48000 = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- 1000 \pm 100 0 ^{2} - 4 \cdot 5 ( - 48000 )}{2 \cdot 5}

100 0^{2} - 4 \cdot 5 (- 48000) = 1400

x_{1, 2} = \frac{- 1000 \pm 1400}{2 \cdot 5}

Separate the solutions

x_{1} = \frac{- 1000 + 1400}{2 \cdot 5}, x_{2} = \frac{- 1000 - 1400}{2 \cdot 5}

x = \frac{- 1000 + 1400}{2 \cdot 5} : 40

x = \frac{- 1000 - 1400}{2 \cdot 5} : - 240

The solutions to the quadratic equation are:

x = 40, x = - 240

(x + 1)^{2} - (2 x + 3)^{2} = 0

3 x + 6 = (x + 4)^{2} - 10

12 x^{2} + 32 x - 64 = 0

8 - t^{2} = 0

t^{2} - 9 t + 20 = 0

What are the solutions to the equation 0.05x^2+10x-480=0 ?
The solutions to the equation 0.05x^2+10x-480=0 are x=40,x=-240
Find the zeros of 0.05x^2+10x-480=0
The zeros of 0.05x^2+10x-480=0 are x=40,x=-240