What are the solutions to the equation 4y^2-5y=6 ?

The solutions to the equation 4y^2-5y=6 are y=2,y=-3/4

Find the zeros of 4y^2-5y=6

The zeros of 4y^2-5y=6 are y=2,y=-3/4

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4 y^{2} - 5 y = 6

y = 2, y = - \frac{3}{4}

Decimal Notation

y = 2, y = - 0.75

Solution steps

4 y^{2} - 5 y = 6

Move

6

to the left side

4 y^{2} - 5 y - 6 = 0

Solve with the quadratic formula

y_{1, 2} = \frac{- ( - 5 ) \pm ( - 5 ) ^{2} - 4 \cdot 4 ( - 6 )}{2 \cdot 4}

(- 5)^{2} - 4 \cdot 4 (- 6) = 11

y_{1, 2} = \frac{- ( - 5 ) \pm 11}{2 \cdot 4}

Separate the solutions

y_{1} = \frac{- ( - 5 ) + 11}{2 \cdot 4}, y_{2} = \frac{- ( - 5 ) - 11}{2 \cdot 4}

y = \frac{- ( - 5 ) + 11}{2 \cdot 4} : 2

y = \frac{- ( - 5 ) - 11}{2 \cdot 4} : - \frac{3}{4}

The solutions to the quadratic equation are:

y = 2, y = - \frac{3}{4}

3 (x - 4) (x - 2) + (x - 1)^{2} = 0

12 x^{2} - 10 x - 12 = 0

3 x^{2} + 6 x - 5 = 4

(b + 7)^{2} = 0

x, 2 x^{2} - k x + 4 = 0

What are the solutions to the equation 4y^2-5y=6 ?
The solutions to the equation 4y^2-5y=6 are y=2,y=-3/4
Find the zeros of 4y^2-5y=6
The zeros of 4y^2-5y=6 are y=2,y=-3/4