What are the solutions to the equation p^2-9p=-8 ?

The solutions to the equation p^2-9p=-8 are p=8,p=1

Find the zeros of p^2-9p=-8

The zeros of p^2-9p=-8 are p=8,p=1

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p^{2} - 9 p = - 8

p = 8, p = 1

Solution steps

p^{2} - 9 p = - 8

Move

8

to the left side

p^{2} - 9 p + 8 = 0

Solve with the quadratic formula

p_{1, 2} = \frac{- ( - 9 ) \pm ( - 9 ) ^{2} - 4 \cdot 1 \cdot 8}{2 \cdot 1}

(- 9)^{2} - 4 \cdot 1 \cdot 8 = 7

p_{1, 2} = \frac{- ( - 9 ) \pm 7}{2 \cdot 1}

Separate the solutions

p_{1} = \frac{- ( - 9 ) + 7}{2 \cdot 1}, p_{2} = \frac{- ( - 9 ) - 7}{2 \cdot 1}

p = \frac{- ( - 9 ) + 7}{2 \cdot 1} : 8

p = \frac{- ( - 9 ) - 7}{2 \cdot 1} : 1

The solutions to the quadratic equation are:

p = 8, p = 1

b^{2} - 13 b + 40 = 0

x, 3 x^{2} + 5 y^{2} - 12 x - 30 y + 60 = 0

x, f = x^{2} + 1 gx + 1

(x - 3) (x + 1) + 4 = 0

x^{2} + (- 1) x + (- 1) + 8 = 0

What are the solutions to the equation p^2-9p=-8 ?
The solutions to the equation p^2-9p=-8 are p=8,p=1
Find the zeros of p^2-9p=-8
The zeros of p^2-9p=-8 are p=8,p=1